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Characteristics of Equilibrium Constant

A zinc rod is...

Question

A zinc rod is dipped in $0.1$ M solution of $Z n S O_{4}$ . The salt is $95 %$ dissociated at this $298$ K. Calculate the electrode potential $[E_{Z n^{+ +} / Z n}^{0} = - 0.76 e V]$ .

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Solution

${Z n S o}_{4} \to {Z n}^{2 +} + {S O}_{4}^{2 -}$
$0.95 \times 0.1$
$= 0.095 m o l / L$
${Z n}^{2 +} + {2 e}^{-} \to Z n$
$E_{c e l l} = E^{0} - \frac{0.059}{2} l o g ⎡ ⎢ ⎢ ⎣ \frac{1}{[{Z n}^{2 +}]} ⎤ ⎥ ⎥ ⎦$
$E_{c e l l} = - 0.76 - \frac{0.059}{2} l o g [\frac{1}{0.095}]$
$E_{c e l l} = - 0.790 V$

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