Question

a⁶ $-$ b⁶

Answer 1

$$\begin{gathered} a^6-b^6 \\ ={\left(a^2\right)}^3-{\left(b^2\right)}^3 \\ =\left(a^2-b^2\right)\left[{\left(a^2\right)}^2+a^2{b}^2+{\left(b^2\right)}^2\right] \\ =\left(a+b\right)\left(a-b\right)\left(a^4+a^2{b}^2+b^4\right) \end{gathered}$$