Ab-2 is a factor of 4ab-3-ab-2-ab-5-True-False-

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Factors

ab^2 is a fac...

Question

$a b^{2}$ is a factor of $4 a b^{3} - a b^{2} + a b^{5}$ .

True

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False

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Solution

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Similar questions

{(\frac{4}{11})}^{6} = \frac{4^{}}{11^{}}

{(\frac{- 5}{17})}^{3} = \frac{{(- 5)}^{}}{17^{}}

{(\frac{1}{10})}^{20} = \frac{1}{10^{}}

{(\frac{a}{b})}^{2} = \frac{a^{}}{b^{}}

{(\frac{6}{7})}^{3} = \frac{6^{}}{7^{}}

{(\frac{5}{7})}^{8} = \frac{5^{}}{7^{}}

{(\frac{x}{y})}^{7} = \frac{x^{}}{y^{}}

{(\frac{1}{5})}^{3} = \frac{1^{}}{5^{}}

Factorise :

$a b^{2} + (a - 1) b - 1$

$a b^{2}$ is a factor of $4 a b^{3} - a b^{2} + a b^{5}$ .

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