AB - BC - BD - AC and CE bisects - C - - A -30- Then what is - CED -A- 30-B- 45-C- 65-D- 60-

The correct option is D 60°∠ACB= 60^∘ ∠DCE=∠ECB= 30^∘ Therefore, ∠CED= 60^∘. Option (b) ...

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Triangles

AB ⊥ BC , BD ...

Question

AB $⊥$ BC, BD $⊥$ AC and CE bisects $∠$ C, $∠$ A = 30 $^{\circ}$ . Then what is $∠$ CED?

30°

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60°

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45°

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65°

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∠

∠

^{\circ}

A B ⊥ B C, B D ⊥ A C

C E

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∠ C E D

In the given figure, ABCD is a parallelogram, M is the midpoint of BD and BD bisects $∠ B$ as well as $∠ D$ . Then, $∠ A M B =$ ?

(a) $45^{\circ}$

(b) $60^{\circ}$

(d) $30^{\circ}$

In the figure, it is given that $∠$ A = $90^{\circ}$ , AB = AC, and point D bisects the side BC. Find $∠$ ADC.

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