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Question

AB is a part of another large circuit. Also VQVB=12 V Then



A
Current, i=3 A
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B
Current i=5 A
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C
VAVB=12 V
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D
VAVB=24 V
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Solution

The correct options are
A Current, i=3 A
D VAVB=24 V



Applying KVL from Q to B
VQ2i3i=VBVQVB=3i+312=3i+3i=3 A

Applying KVL to the loop
62(ii1)+i1=06=3i16i1=4 A

Applying KVL from A to B
VA2(3)+104(3)4(1)2(3)33(1)=VBVAVB=24 V

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