ABC is a right angled triangle. Find the length of AB.
Given that BC = 12 units; AC = 13 units.
11 units
7 units
4 units
5 units
In ΔABC, by applying Pythagoras theorem, AB2 + BC2 = AC2; where AC is the hypotenuse. AB = √AC2−BC2 = √132−122 = √169−144 = √25 = 5 units
ΔABC is a right angled triangle. Find the length of AC. Given that BC = 3 units; AB = 4 units.
△ ABC a right-angled triangle, find the length of BD assuming △ABC∼△BDC
The area of a square field is 169 sq. units. The length of its side is: