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Question

ABC is a right angled triangle in which AB=3 cm and BC=4 cm . And ABC=π2. The three charges +15, +12 and -20 e.s.u. are placed respectively on A, B and C. The force acting on B is

A
125 dynes
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B
35 dynes
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C
25 dynes
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D
Zero
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Solution

The correct option is C 25 dynes
Net force on B Fnet=F2A+F2C



FA=15×12(3)2=20 dyne,FC=12×20(4)2=15 dyne
Fnet=F2A+F2C=(20)2+(15)2=25 dyne

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