ABC is a triangle, right-angled at C. If AB = 25 cm and AC = 7 find BC

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Solution

BY pythagorean triplet
$A B^{2} = A C^{2} + B C^{2} \Rightarrow (25 \times 25)^{2} = 7^{2} + B C^{2} \Rightarrow 625 = 49 + B C^{2} \Rightarrow B C^{2} = 625 - 49 \Rightarrow B C^{2} = 576 B C = \sqrt{576} = 24 c m$

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Similar questions

$A B C$ is a triangle right angled at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

A B = 25

A C = 7

$A B C$ is a triangle, right angles at $C$ . If $A B = 25 c m$ and $A C = 7 c m$ , find $B C$ .

Question 2
ABC is a triangle, right angled at C. If AB = 25 cm and AC = 7 cm, find BC.

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