Question

ABC is an isosceles triangle such that AB=AC and $\angle B=35$. AD is the median to the base BC. Then $\angle BAD$ is :

• A. 70
• B. 35
• C. 110
• D. 55

Answer 1

The correct option is D 55

ABC is an isosceles triangle since AB=AC. $\angle B=\angle C={35}^{\circ }$

$\angle A={110}^{\circ }(\because \angle A+\angle B+\angle C={180}^{\circ })$

In an isosceles triangle, median (AD) to the base BC is the angular bisector of $\angle A$

Hence, $\angle BAD={55}^{\circ }$