Question

$∆$ABC is isosceles triangle where seg AB $\cong$ seg AC write two different congruent correspondences between the vertices, by which the $∆$ABC is congruent to itself.

Answer 1

$$\begin{gathered} \mathrm{Given}:△\mathrm{ABC}\mathrm{is}\text{an}\mathrm{isosceles}\mathrm{triangle}. \\ \angle \mathrm{A}=\angle \mathrm{A}\left(\mathrm{common}\right) \\ \mathrm{seg}\mathrm{AB}\cong \mathrm{seg}\mathrm{AC} \\ \angle \mathrm{B}=\angle \mathrm{C}(\because \mathrm{AB}=\hspace{0.17em}\mathrm{AC}) \\ \mathrm{Thus},△\mathrm{ABC}\cong △\mathrm{ACB}(\mathrm{ASA}\mathrm{test}) \end{gathered}$$