Question

ABC is right angled triangle, right angle at B, $AC=25$, $AB=7$ then BC= ?

• A. $20$
• B. $21$
• C. $23$
• D. $24$

Answer 1

Answer: (D)

$24$

In this triangle angle $C=90$

Line AB is hypotenuse which was $25cm$ or line $AC$ was Perpendicular which was 7$cm$

Therfore $H^2=P^2+B^2$

Therfore $H^2=P^2+B^2$

${25}^2=7^2+B^2$

$625=49+B^2$

$625-49=B^2$

$\sqrt{576}=B$

so Base=$24cm.$