ABCD is a cyclic quadrilateral of a circle with centre O such that AB is a diameter of this circle and the length of the chord CD is equal to the radius of the circle. If AD and BC produced meet at P, show that APB=60∘.
Given
In :
In (Radius of the same circle)
Let
Therefore … … … (i)
In (Radius of the same circle)
Let
Therefore … … … (ii)
Now, (straight line angle)
In :