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Question
ABCD is a parallelogram and EFGB is a rhombus. AB = 7cm; AD = 4cm. If E is the mid-point of BC, find the perimeter of the whole figure i.e., ABGFECDA.
ABCD is a parallelogram and EFGB is a rhombus. AB = 7cm; AD = 4cm. If E is the mid-point of BC, find the perimeter of the whole figure i.e., ABGFECDA.
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Solution
The correct option is C 26 cm
AB = DC = 7 cm
AD = BC = 4 cm
Since E is the midpoint,
BE = EC = 2 cm
Since EFGB is a rhombus all sides are equal in length.
EF= FG = GB = 2cm
Perimeter of ABGFECDA = AB + BG + GF + FE + EC + CD + DA
= (7+ 2 + 2 + 2 + 2 + 7 + 4) cm
= 26 cm
26 cm
AB = DC = 7 cm
AD = BC = 4 cm
Since E is the midpoint,
BE = EC = 2 cm
Since EFGB is a rhombus all sides are equal in length.
EF= FG = GB = 2cm
Perimeter of ABGFECDA = AB + BG + GF + FE + EC + CD + DA
= (7+ 2 + 2 + 2 + 2 + 7 + 4) cm
= 26 cm
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