ABCD is a rectangle whose sides AB has equation 3x-12y+5 =0. Find the slopes of the other sides of the rectangle

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Solution

The given equation is of the form ax+by+c = 0

Slope of such equation = - a / b

As we know that Line AB is perpendicular to DA, the product of their slopes must be -1.

So slope of AB is -3/-12= 3/12

=1/4

1/4 * slope of DA = -1

Therefore slope of DA = -4.

Since parallal lines have same slope,

Slope of AB=CD=1/4
Slope of BC=DA= -4

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