Question

In the figure, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of $△EFG.$

Answer 1

ABCD is a rectangle in which AB = 10 cm, AD = 5 cm

$\because$ ABCD is a rectangle
$\therefore$ DC || AB,
DC is produced to E and AB is produced to G
$\therefore$ DE || AG
$\because$ Rectangle ABCD and ||gm ABEF are on the same base AB and between the same parallels
$\therefore$ ar(rect. ABCD ) = ar(||gm ABEF)
$=AB\times AD=10\times 5=50c{m}^2$
Now ||gm ABEF and $△EFG$ are on the same base EF and between the same parallels
$\therefore area△EFG=\frac{1}{2}ar\left(||gmABEF\right)=\frac{1}{2}\times 50=25c{m}^2$