Question

$ABCD$ is a rhombus with $\angle ABC={56}^{\circ }$. Determine $\angle ACD$.

Answer 1

Since, $ABCD$ is a rhombus, therefore, adjacent angles will be supplementary.

$\therefore \angle BCD={180}^{\circ }-{56}^{\circ }={124}^{\circ }$

Also, diagonals of rhombus, bisect the vertex angles.

$\therefore \angle ACD=\frac{1}{2}\times {124}^{\circ }={62}^{\circ }$