Question

ABCD is a rhombus with $\angle ABC={56}^{\circ }$ and $\angle BAC={62}^{\circ }$, then $\angle ACD$ is equal to:

• A. ${90}^{\circ }$
• B. ${60}^{\circ }$
• C. ${56}^{\circ }$
• D. ${62}^{\circ }$

Answer 1

The correct option is D ${62}^{\circ }$

$\angle C^{\prime }+\angle B+\angle A^{\prime }={180}^o\Rightarrow \angle C^{\prime }={62}^o$

As diagonal of rhombus

bisects the opp. angles

$\Rightarrow \theta =\angle ACB=\angle C^{\prime }={62}^o$