ABCD is a trapezium in which AB || DC. M and N are the mid-points of AD and BC respectively. If AB = 12 cm, MN = 14 cm, then CD =
16 cm
In trapezium ABCD, AB|| DC. M and N are mid-points of sides AD and BC and MN is joined. AB = 12 cm, MN = 14 cm
∵MN=12(AB+CD)⇒2MN=AB+CD⇒2×14=12+CDCD=2×14−12=28−12=16cm