About 6 g of impure NaCl is dissolved in water and then treated with excess of silver nitrate solution. The weight of silver chloride precipitated was found to be 14 g. The percentage purity of the NaCl solution would be:
A
95%
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B
85%
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C
75%
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D
65%
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Solution
The correct option is A 95% The reaction that takes place is: NaCl+AgNO2→AgCl↓+NaNO3 ...143.5g of AgCl is produced from 58.5 g NaCl. ... 14 g of AgCl is produced from 58.5 g NaCl 58.5×14143.5=5.70
This is the amount of NaCl in common salt: % purity =5.706×100=95%