Absolute mass of a proton is equal to __________.

9.109 \times 10^{- 31}

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- 1.602 \times 10^{- 31}

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1.672 \times 10^{- 27}

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1.674 \times 10^{- 27}

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Solution

The correct option is C $1.672 \times 10^{- 27}$ kg
The mass of proton is equal to $1.672 \times 10^{- 27}$ kg.

Hence the correct option is C.

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1.813 \times 10^{- 4} .

9.109 \times 10^{- 31} k g)

= 1.6725 \times 10^{- 27} k g

= 1.6725 \times 10^{- 27} k g

= 9 \times 10^{- 31} k g

9.109 \times 10^{- 31}

1.758820 \times 10^{11} {C kg}^{- 1}

1.758820 \times 10^{11} C k g^{- 1}

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