Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron $= 1.6725 \times 10^{- 27} k g$ , mass of proton $= 1.6725 \times 10^{- 27} k g$ , mass of electron $= 9 \times 10^{- 31} k g$ )

5.4 M e V

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0.73 M e V

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7.10 M e V

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6.30 M e V

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Solution

The correct option is B $0.73 M e V$
A neutron breaks into a proton and electron.
mass of neutron $= 1.6725 \times 10^{- 27} k g$
mass of proton $= 1.6725 \times 10^{- 27} k g$
mass of electron $= 9 \times 10^{- 31} k g$
$Δ m = (m_{p} + m_{e}) - m_{n}$
$= 9 \times 10^{- 31} k g$
Energy released $= (9 \times 10^{- 31} k g) C^{2} J o u l e$
$= \frac{9 \times 10^{- 3} \times {(3 \times 10^{8})}^{2}}{1.6 \times 10^{- 13}} M e V$
$= 0.73 M e V$

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Similar questions

Q. A neutron breaks into a proton and an electron. Calculate the energy produced in this reaction is MeV. Mass of an electron

= 9 \times 10^{- 31} k g

, mass of proton

= 1.6725 \times 10^{- 27} k g

, mass of neutron

= 1.6747 \times 10^{- 27} k g

, and speed of light

= 3 \times 10^{8} m s^{- 1}

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1.60 \times 10^{- 27} k g

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An electron and a proton are detected in a cosmic ray experiment, the first with kinetic energy 10 keV, and the second with 100 keV. Which is faster, the electron or the proton? Obtain the ratio of their speeds. (electron mass = 9.11 × 10^–31 kg, proton mass = 1.67 × 10^–27 kg, 1 eV = 1.60 × 10^–19 J).

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Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron =1.6725×10−27kg, mass of proton =1.6725×10−27kg, mass of electron =9×10−31kg )

The correct option is B 0.73MeVA neutron breaks into a proton and electron.mass of neutron =1.6725×10−27kgmass of proton =1.6725×10−27kgmass of electron =9×10−31kgΔm=(mp+me)−mn =9×10−31kgEnergy released =(9×10−31kg)C2Joule =9×10−3×(3×108)21.6×10−13MeV =0.73MeV

Assume that a neutron breaks into a proton and an electron. The energy released during this process is : (mass of neutron $= 1.6725 \times 10^{- 27} k g$ , mass of proton $= 1.6725 \times 10^{- 27} k g$ , mass of electron $= 9 \times 10^{- 31} k g$ )