Accelerates uniformly from 18 km per hour to 36 kilometre per hour in 5 seconds. Calculate:-

1) the acceleration and

2) the distance covered by the car in that time

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Solution

Acceleration = Change in Velocity/Time
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (55)+(1/2155)
s=25+12.5
s=37.5 m

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Accelerates uniformly from 18 km per hour to 36 kilometre per hour in 5 seconds. Calculate:- 1) the acceleration and 2) the distance covered by the car in that time

Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s2 Equation of motion,s=ut+(1/2)at2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (5*5)+(1/2*1*5*5) s=25+12.5 s=37.5 m

Accelerates uniformly from 18 km per hour to 36 kilometre per hour in 5 seconds. Calculate:-

1) the acceleration and

2) the distance covered by the car in that time

Acceleration = Change in Velocity/Time
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (55)+(1/2155)
s=25+12.5
s=37.5 m