Question

Acceleration-time graph for a particle is given in the figure. If it starts motion at $t=0$, distance traveled in $3s$ will be

• A. $4m$
• B. $2m$
• C. $0$
• D. $6m$

Answer 1

The correct option is A $4m$

$1^{st}$ second
distance traveled$=ut+\frac{1}{2}a{t}^2$
$=0+\frac{1}{2}\times 2\times 1\times 1=1m$
$v=u+at,v=0+2\times 1=2m/s$
$2^{nd}$ second
$s=ut=2\times 1=2m$
$3^{rd}$ second
$s=ut+\frac{1}{2}a{t}^2=2\times 1\times -\frac{1}{2}\times 2\times 1\times 1=2-1=1m$
Total distance$=4m$