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Question
Acceleration-time graph of a particle executing SHM is as shown in the figure. Select the correct alternative(s)
Acceleration-time graph of a particle executing SHM is as shown in the figure. Select the correct alternative(s)
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Solution
The correct options are
A Displacement of particle at 1 is negative
B Speed of particle at 4 is decreasing
C Velocity of particle at 2 is positive
D Potential energy of particle at 3 is maximum
Area under v-t graph shows the displacement and the slope of the v-t graph shows acceleration.
So at point 1, area of v-t graph is negative. which means at point 1, displacement is negative. so A is incorrect.
At point 2, area of v-t graph is negative, which means at point 2, displacement is negative, so B is correct.
At point 3, slope of v-t graph is positive, which means at point 3, acceleration is positive, so C is correct.
At point 4, slope of v-t graph is zero, which means at point 4, acceleration is zero, so D is incorrect.
A Displacement of particle at 1 is negative
B Speed of particle at 4 is decreasing
C Velocity of particle at 2 is positive
D Potential energy of particle at 3 is maximum
Area under v-t graph shows the displacement and the slope of the v-t graph shows acceleration.
So at point 1, area of v-t graph is negative. which means at point 1, displacement is negative. so A is incorrect.
At point 2, area of v-t graph is negative, which means at point 2, displacement is negative, so B is correct.
At point 3, slope of v-t graph is positive, which means at point 3, acceleration is positive, so C is correct.
At point 4, slope of v-t graph is zero, which means at point 4, acceleration is zero, so D is incorrect.
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