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Byju's Answer
Standard VII
Mathematics
Pythagoras Theorem
According to ...
Question
According to Apolloneous Theorem, if
¯
¯¯
¯
A
D
is a median of
△
A
B
C
, then
A
B
2
+
A
C
2
=
A
A
D
+
B
D
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B
A
D
−
B
D
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C
2
(
A
D
2
+
B
D
2
)
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D
2
(
A
D
2
−
B
D
2
)
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Solution
The correct option is
C
2
(
A
D
2
+
B
D
2
)
T
h
e
n
,
A
B
2
+
A
C
2
=
?
A
D
i
s
m
e
d
i
a
n
⇒
A
B
2
+
A
C
2
=
2
∣
∣
B
C
2
4
∣
∣
+
2
A
D
2
[
B
C
=
2
B
D
o
r
B
C
=
D
C
]
⇒
A
B
2
+
A
C
2
=
2
∣
∣
B
C
2
∣
∣
2
+
2
A
D
2
A
B
2
+
A
C
2
=
2
B
D
2
+
2
A
D
2
=
2
(
A
D
2
+
B
D
2
)
Suggest Corrections
0
Similar questions
Q.
In
△
A
B
C
, if
A
D
is the median, show that
A
B
2
+
A
C
2
=
2
(
A
D
2
+
B
D
2
)
.
Q.
In a triangle ABC, if AD is the median, then show that
A
B
2
+
A
C
2
=
2
(
A
D
2
+
B
D
2
)
Q.
In this question
In a triangle ABC , AB>AC , AD is perpendicular to BC , prove that
AB 2 - AC
2
= BD 2= CD2
I have done it like this
In triangle ABD
AD2. = AB2 -. BD2. EQUATION 1
In triangle ADC
AD2 =. AC2 - CD2. EQUATION 2
on combining. EQUATION 1 and 2
AD2 = AB2. -. BD 2
AD2 = AC2 - CD2.
AB2 -. AC2 =. BD2 - CD2
hence proved
IS THIS CORRECT
Q.
In
△
ABC, AD is a median. Prove that
A
B
2
+
A
C
2
=
2
(
A
D
2
+
D
C
2
)
.
Q.
If in
△
A
B
C
,
A
D
is median and
A
E
⊥
B
C
, then prove that
A
B
2
+
A
C
2
=
2
A
D
2
+
1
2
B
C
2
.
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