According to Bohr's the third shell of atom contain 18 electron but in the whole chapter it is said that second and the above cell have only 8 electron capability.
Upto the 2nd shell we have 8 electrons.
Then in 3rd shell according to the formula 2n^2 we must have 18 electrons but we take only 8.
Now if you go deep in the arrangement of electrons in case of subshells we have a particular order.
Each shell is divided into subshells
Each subshell accommodates diffrent no. Of electrons….
As
‘s’ accomodates 2
‘p’ accomodates 6
‘d’ accomodates 10
‘f’ accomodates 14
And so on..!!
In K shell we have only ‘s’ subshell total 2 electrons
In L shell we have ‘s’ and ‘p’ subshells total 8 electrons.
In M shell we have ‘s’, ‘p’ and ‘d’ subshell total 18 electrons.
In N shell we have ‘s’, ‘p’, ‘d’ and ‘f’ subshell total 32 electrons.
And further…!!
So when we see the first 20 elments, we see that filling continues in N shell after Neon (atomic no. 10) and we have three subshells here out of which two accomodate 8 electrons and rest 10 are accomodated later (after filling of ‘s’ subshell of N shell)
So somewhat it is applicable till first 20 elements.