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Question

According to Bohr's the third shell of atom contain 18 electron but in the whole chapter it is said that second and the above cell have only 8 electron capability.

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Solution

Upto the 2nd shell we have 8 electrons.

Then in 3rd shell according to the formula 2n^2 we must have 18 electrons but we take only 8.

Now if you go deep in the arrangement of electrons in case of subshells we have a particular order.

Each shell is divided into subshells

Each subshell accommodates diffrent no. Of electrons….

As

‘s’ accomodates 2

‘p’ accomodates 6

‘d’ accomodates 10

‘f’ accomodates 14

And so on..!!

In K shell we have only ‘s’ subshell total 2 electrons

In L shell we have ‘s’ and ‘p’ subshells total 8 electrons.

In M shell we have ‘s’, ‘p’ and ‘d’ subshell total 18 electrons.

In N shell we have ‘s’, ‘p’, ‘d’ and ‘f’ subshell total 32 electrons.

And further…!!

So when we see the first 20 elments, we see that filling continues in N shell after Neon (atomic no. 10) and we have three subshells here out of which two accomodate 8 electrons and rest 10 are accomodated later (after filling of ‘s’ subshell of N shell)

So somewhat it is applicable till first 20 elements.


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