CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

According to Bohr's the third shell of atom contain 18 electron but in the whole chapter it is said that second and the above cell have only 8 electron capability.

Open in App
Solution

Upto the 2nd shell we have 8 electrons.

Then in 3rd shell according to the formula 2n^2 we must have 18 electrons but we take only 8.

Now if you go deep in the arrangement of electrons in case of subshells we have a particular order.

Each shell is divided into subshells

Each subshell accommodates diffrent no. Of electrons….

As

‘s’ accomodates 2

‘p’ accomodates 6

‘d’ accomodates 10

‘f’ accomodates 14

And so on..!!

In K shell we have only ‘s’ subshell total 2 electrons

In L shell we have ‘s’ and ‘p’ subshells total 8 electrons.

In M shell we have ‘s’, ‘p’ and ‘d’ subshell total 18 electrons.

In N shell we have ‘s’, ‘p’, ‘d’ and ‘f’ subshell total 32 electrons.

And further…!!

So when we see the first 20 elments, we see that filling continues in N shell after Neon (atomic no. 10) and we have three subshells here out of which two accomodate 8 electrons and rest 10 are accomodated later (after filling of ‘s’ subshell of N shell)

So somewhat it is applicable till first 20 elements.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Atomic Valency
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon