According to Bohr's theory, the angular momentum for an electron of 3rd orbit is:

\frac{3 h}{2 π}

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\frac{1.5 h}{2 π}

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\frac{9 h}{2 π}

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\frac{2 h}{π}

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Solution

The correct option is B $\frac{3 h}{2 π}$
Angular momentum:

$m v r = \frac{n h}{2 π}$

Given that n=3

$m v r = \frac{3 h}{2 π}$

Hence, the correct option is $A$

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