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Question

# According to Bohr's theory, the electronic energy of hydrogen atom in the Bohr's orbit is given byEn = 21.76×10−19n2 JThe longest wavelength in Ao of light will be needed to remove an electron from the third orbit of the He+:

A
2050 A
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B
2450 A
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C
2250 A
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D
none of these
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Solution

## The correct option is A 2050 AEn = -21.76×10−19n2 JFor He⊕, En = -21.76×10−19×z2n2 JE3(for He⊕ = -21.76×10−19×2232 J = -9.68 × 10−19 JEnergy required to remove an e− form the third Bohr orbit of He⊕ΔE = 0 - E3 = 0 -(-9.68 × 10−19 J)=9.68 × 10−19 J (Since IE is +ve)Since Δ E = -hcλ J = 9.68 × 10−19 Jλ = -hcΔE = -6.266×10−34Js×3×108m9.68×10−19J = 2.05 × 106−7 m = 2050 × 10−10 m = 2050 A

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