Question

According to Bronsted-Lowry concept, the relative strengths of the bases $C{H}_{3}CO{O}^{-}$, $O{H}^{-}$ and $C{l}^{-}$ are in the order:

• A. $O{H}^{-}>C{H}_{3}CO{O}^{-}>C{l}^{-}$
• B. $C{l}^{-}>O{H}^{-}>C{H}_{3}CO{O}^{-}$
• C. $C{H}_{3}CO{O}^{-}>O{H}^{-}>C{l}^{-}$
• D. $O{H}^{-}>C{l}^{-}>C{H}_{3}CO{O}^{-}$

Answer 1

The correct option is A $O{H}^{-}>C{H}_{3}CO{O}^{-}>C{l}^{-}$

$O{H}^{-},C{H}_{3}CO{O}^{-},C{l}^{-}$ are the conjugate bases of $H_{2}O,C{H}_{3}COOH,HCl$ respectively.
We know,
$HCl>C{H}_{3}COOH>H_{2}O\text{acid strength}$
$\therefore C{l}^{-}<C{H}_{3}CO{O}^{-}<O{H}^{-}\text{basic strength}$
Stronger the acid, weaker will be its conjugate base.