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B
(dVdT)P=K
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C
(1T−VT2)=0
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D
None of these
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Solution
The correct option is B(dVdT)P=K From the ideal gas equation, PV=nRT V=nRTP at constant pressure and number of moles V=KT Upon differentiating, (dV=KdT)P (dVdT)P=K This is the differential form of Charle's law.