Question

According to de Broglie, the electron in n=3 of Hydrogen atom will look like

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

From Bohr's quantisation of angular momentur of electron,

$mvr=n\frac{h}{2\pi }\left(1\right)$

From, de Broglie equation,

$mv=\frac{h}{\lambda }\left(2\right)$

Dividing equation 1 by 2 will give:

$r=n\frac{\lambda }{2\pi }\Rightarrow 2\pi r=n\lambda$

So, the total circumference for third orbit will be equal to three times the wavelength. Hence, option (a) is correct.