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Matter Waves

According to ...

Question

According to de Broglie, The relation between the wavelength of the wave associated with the moving electron and momentum of the electron is $λ = \frac{h}{m v}$ .

A

True

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B

False

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Solution

The correct option is A True
De-Broglie gave relationship between wavelength and momentum of a body. The relationship is
$λ = \frac{h}{m v} = \frac{h}{p}$
Hence given statement is true.

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Similar questions

Q. According to de-Broglie hypothesis, the wavelength associated with moving electron of mass

^{'} m^{'}

^{'} λ_{e}^{'}

. Using mass energy relation and Planck's quantum theory, the wavelength associated with photon is

^{'} λ_{p}^{'}

. If the energy

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^{'} λ_{e}^{'}

^{'} λ_{p}^{'}

Q. What should be the ratio of velocities of

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According to be Broglie equation =

λ = \frac{h}{m v}

Dual nature of matter was proposed by de Broglie in 1923, it was
experimentally verified by Davisson and Germer by diffraction
experiment. Wave character of matter has significance only for
microscopic particles. de Broglie wavelength or wavelength of
matter wave can be calculated using the following relation:

λ = \frac{h}{m v}

m

v

' are the mass and velocity of the particle.
de Broglie hypothesis suggested that electron waves were being
diffracted by the target, much as

X

-rays are diffracted by planes of
atoms in the crystals.

The wavelength of matter waves associated with a body of mass

1000 g

moving with a velocity of

100 m / s e c

The French physicist Louis de Broglie in 1924 postulated that matter, like radiation, should exhibit a dual behavior. He proposed the following relationship between the wavelength

λ

of a material particle, its linear momentum p and Planck constant h.

λ = \frac{h}{p} = \frac{h}{m v}

The de Broglie relation implies that the wavelength of a particle should decrease as its velocity increases. It also implies that for a given velocity heavier particles should have a shorter wavelength than lighter particles. The waves associated with particles in motion are called matter waves or de-Broglie waves. These waves differ from the electromagnetic wave as they
(i) have lower velocities
(ii) have no electrical and magnetic fields and
(iii)are not emitted by the particle under consideration
The experimental confirmation of the de Broglie relation was obtained when Davisson and Germer, in 1927, observed that a beam of electrons is diffracted by a nickel crystal. As diffraction is a characteristic property of waves, hence the beam of electron behaves as a wave, as proposed by de Broglie.

If proton, electron and

α

-particle are moving with same kinetic energy then the order of their de-Broglie's wavelength.

Q. Write the formula for de Broglie wavelength. An electron is moving with speed of

0.5 \times 10^{3} m / s

. Find the de Broglie wavelength associated with it.

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