Question

According to Hardy-Weinberg's principle the allele frequency of a population remains constant. If frequency of dominant allele is $0.6$ than give frequency of heterozygous population.

Answer 1

Allele frequency is determined by the relative frequency of a specific allele an autosomal locus in a population, in accordance with the Hardy-Weinberg equilibrium rule the allelic frequencies (frequency of recessive and dominant allele) in a particular population will not change from one generation to the next, if there is no mutation, assortative mating, selection, migration, and genetic drift. According to the Hardy-Weinberg equation p2 + 2pq + q2 = 1, where p denotes dominant allele frequency, q denotes recessive allele frequency, the p2= frequency of the homozygous dominant allele, the q2= frequency of the recessive allele, the 2pq= frequency of the heterozygous allele.

In this question, p=0.6; hence, => q = 0.4

Thus, heterozygous frequency will be 2pq= 2x.06x0.4=0.48