Question

According to Kohlrausch law, the limiting value of molar conductivity of an electrolyte $A_{2}B$ is:

• A. ${\lambda }_{\left(A^{\oplus }\right)}^{\infty }+{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$
• B. ${\lambda }_{\left(A^{\oplus }\right)}^{\infty }-{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$
• C. $2{\lambda }_{\left(A^{\oplus }\right)}^{\infty }+\frac{1}{2}{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$
• D. $2{\lambda }_{\left(A^{\oplus }\right)}^{\infty }+{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$

Answer 1

The correct option is D $2{\lambda }_{\left(A^{\oplus }\right)}^{\infty }+{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$

KOHLRAUSCH LAW : This law states the equivalent conductivity of any electrolyte at infinite dilution, eq. conductances of the cation and anion given by the electrolytes at infinite dilution.

So here,

$\lambda =2{\lambda }_{\left(A^{\oplus }\right)}^{\infty }+{\lambda }_{\left(B^{\ominus }\right)}^{\infty }$