According to Lewis dot structure the number of bond around central atom is greater than four for which of the following anion :

C O_{3}^{2 -}

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N O_{3}^{-}

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C O_{4}^{3 -}

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none of the above

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Solution

The correct option is D $C O_{4}^{3 -}$
C is the correct answer.
$C O_{4}^{3 -}$ has $5$ bonds.

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Similar questions

C O_{3}^{2 -}

H C l O_{4}

H N O_{3}

The number of electrons in a Lewis dot structure of each bonded atom should always sum up to:

O F_{2}

{[: ¨ N = N = ¨ N :]}^{-}

N

O_{2}

{C O}_{3}^{2 -}

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