According to $M O$ theory which of the following lists ranks the nitrogen species in terms of increasing bond order?

N_{2}^{-} < N_{2}^{2 -} < N_{2}

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N_{2}^{-} < N_{2} < N_{2}^{2 -}

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N_{2}^{2 -} < N_{2}^{-} < N_{2}

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N_{2} < N_{2}^{2 -} < N_{2}^{-}

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Solution

The correct option is A $N_{2}^{2 -} < N_{2}^{-} < N_{2}$
Let us calculate the bond order of all the ions and molecules.
We know that
Bond order $= \frac{n o . o f b o n d p a i r s - n o . o f a n t i b o n d i n g p a i r s}{2}$
For $N_{2}^{2 -}$
Bond order $= \frac{10 - 6}{2} = 2$
For $N_{2}^{-}$
Bond order $= \frac{10 - 5}{2} = 2.5$
For $N_{2}$
Bond order $= \frac{10 - 4}{2} = 3$

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