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Bond Order by MOT

According to ...

Question

According to Molecular Orbital Theory:

C_{2}^{2 -}

is expected to be diamagnetic

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O_{2}^{2 +}

is expected to have a longer bond length than

O_{2}

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N_{2}^{+}

and

N_{2}^{-}

have the same bond order

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H e_{2}^{+}

has the same energy as two isolated He atoms

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Solution

The correct options are
A $C_{2}^{2 -}$ is expected to be diamagnetic
C $N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order
(A) $C_{2}^{2 -}$ bond order
Bond order $= \frac{T o t a l n o . o f b o n d i n g e l e c t r o n s - T o t a l n o . o f a n t i b o n d i n g}{2}$
Total no. of electrons in $C_{2}^{2 -}$ is $14$
$σ {1 S}^{2} σ^{} {1 S}^{2} σ {2 S}^{2} σ^{} {2 S}^{2} Π {2 P}_{y}^{2} Π 2 P_{2}^{2} σ {2 P}_{x}^{2}$
Bond order $= \frac{10 - 4}{2} = 3$
If bond order is in integers then moleculelion is diamagnetic.
(B) $B o n d o r d e r α \frac{1}{B o n d l e n g t h}$
$O_{2}^{2 +}$ bond order is $3$
$O_{2}$ bond order is $2$
(C) $N_{2}^{+}$ and $N_{2}^{-}$ have the same bond order.

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Similar questions

O_{2}

O_{2}^{+}

N_{2}

N_{2}^{+}

Question 19

Which of the following statement is not correct from the view point molecular orbital theory?

(a) $B e_{2}$ is not a stable molecule

(b) $H e_{2}$ is not stable but $H e_{2}^{+}$ is expected to exist.

(d) The order of energies of molecular orbitals in $N_{2}$ molecule is

$σ 2 s < σ^{*} 2 s < σ 2 p_{z} < (π^{*} 2 p_{x} ≃ π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$

O_{2}

N_{2}

N_{2}

N_{2}

N_{2}^{+}

N_{2}

C O^{+}

Question 32

Using molecular orbital theory, compare the bond energy and magnetic character of $O_{2}^{+}$ and $O_{2}^{+}$ species.

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