Question

According to the Bhor Theory , which of the following transitions in the hydrogen atom will give rise to the least energetic photon ?

• A. n=6 to n=1
• B. n = 5 to n = 4
• C. n=6 to n=5
• D. n=5 to n=3

Answer 1

Answer: (C)

n=6 to n=5

The least energetic proton will be a result of a transistion where the energy difference will be the lowest. We know that energy is inversely proportional to the square of n. Hence higher the value of n, lower the energy. Similarly, two high values of n will give the least difference in energy which in this case is $n=6$ to $n=5$