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Question

# According to this equation:△x=12at2We can determine how far an object, starting from rest, has traveled in the x direction if we know its constant acceleration and how long it has traveled.Object M and object N both start from rest and have constant accelerations.If object M has travelled for twice as much time as object N and object M's acceleration is three times that of object N, then how many times further has object M traveled than object N?

A
6
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B
12
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C
18
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D
36
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E
Same distance
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Solution

## The correct option is A 12Distance traveled by object is given as Δx=12at2⟹ ΔxMΔxN=aMt2MaNt2NGiven : tM=2tN aM=3aN∴ ΔxMΔxN=(3aN)(2tN)2aNt2N=12 ⟹ΔxM=12 ΔxN

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