An object starts from rest with constant acceleration of 4 m/s^2 find the distance travelled by that object in 5th half second

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Solution

initial velocity, u=0, a=4m/s2
distance travelled in time t =1/2a(t^2)
distance travelled in 5^th half seconds = total distance travelled – distance travelled in 4^th half seconds
= 1/2[att]-1/2[att]
=1/2[4(5/2)^2]-1/2[4(4/2)^2]
=1/2[4(25-16)/4]
=1/2(9)=4.5m
thus, distance travelled in 5^th half seconds is 4.5m

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