According to Wien's displacement law:

T_{3} > T_{2} > T_{1}

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T_{1} > T_{2} > T_{3}

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T_{3} = T_{2} = T_{1}

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T_{2} > T_{3} > T_{1}

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Solution

The correct option is A $T_{3} > T_{2} > T_{1}$
Given graph describes the Energy density of radiated energy with wavelength at different temperature.

According to Wein's displacement law,
$λ_{m} . T = b$ [constant]

$\Rightarrow T \propto \frac{1}{λ_{m}}$

From the graph, $λ_{m_{1}} > λ_{m_{2}} > λ_{m_{3}}$

$\Rightarrow T_{1} < T_{2} < T_{3}$

Hence, option $(A)$ is correct.

Why this question?

Concept: Temperature of the black body is inversely proportional to the wavelength of the light having maximum intensity emitted by them. It is given by Wein’s displacement law.

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