Question

According to Wien's displacement law:

• A. $T_3>T_2>T_1$
• B. $T_1>T_2>T_3$
• C. $T_3=T_2=T_1$
• D. $T_2>T_3>T_1$

Answer 1

The correct option is A $T_3>T_2>T_1$

Given graph describes the Energy density of radiated energy with wavelength at different temperature.

According to Wein's displacement law,
${\lambda }_m.T=b$ [constant]

$\Rightarrow T\propto \frac{1}{{\lambda }_m}$

From the graph, ${\lambda }_{m_1}>{\lambda }_{m_2}>{\lambda }_{m_3}$

$\Rightarrow T_1<T_2<T_3$

Hence, option $\left(A\right)$ is correct.

Why this question? Concept: Temperature of the black body is inversely proportional to the wavelength of the light having maximum intensity emitted by them. It is given by Wein’s displacement law.