Account for the following
Ko2 is paramagnetic
LiI iodide is more soluble than KI in ethanol

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Solution

KO2 is a superoxide in which, only one electron is released from the dioxygen atom and a superoxide ion is represented as 02 . So, in KO2 the oxygen atoms bear -1/2 oxidation state and they also behave as a free radical species, having an unpaired electron. We know that a molecule becomes paramagnetic due to the presence of unpaired electrons. Hence, KO2 behaves as paramagnetic molecule .

LiI is more soluble than KI in ethanol. As a result of its small size, the lithium ion has a higher polarising power than the potassium ion. It polarises the electron cloud of the iodide ion to a much greater extent than the potassium ion. This causes a greater covalent character in LiI than in KI. Hence, LiI is more soluble in ethanol.

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