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Synthesis of Ethers

Acetaldehyde ...

Question

Acetaldehyde and Propyne can be distinguish by:
(i) Tollen's reagant (ii) $l_{2} / N a O H$ (iii) Lucas reagent (iv) neutral ${F e C l}_{3}$

(ii),(iii) & (iv)

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(ii) & (iii)

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(i) & (ii)

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(iii) & (iv)

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Solution

The correct option is A (ii),(iii) & (iv)
$C H_{3} - C H O$ , $C H_{3} - C \equiv C H$

Tollens's reagent can't differentiate these two compound. Because Tollen's reagent react with aldehyde and terminal alkyne both.

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I_{2} / N a O H

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IV) Aldehydes can reduce Tollen's reagent into silver mirror

O_{2} - \to h v H^{+} - - \to △ A + B

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