Question

Acetaldehyde and propyne can be distinguished by :
i) Tollen's reagent
ii) $I_2/NaOH$
iii) Lucas reagent
iv) neutral $FeC{l}_3$

• A. (i), (ii) & (iii)
• B. (ii) & (iii)
• C. (i) & (ii)
• D. (iii) & (iv)

Answer 1

The correct option is C (i) & (ii)

Acetaldehyde reacts with Tollen's reagent (ammoniacal silver nitrate solution) to form silver mirror. This test is not given by propyne.

Acetaldehyde reacts with iodine in the presence of $NaOH$ to form iodoform. This test is not given by propyne.

Lucas reagent is used to differentiate the $1^o$, $2^o$ and $3^o$ alcohols.

Thus, option C is the correct answer.