Acetaldoxime on reduction with $N a / C_{2} H_{5} O H$ gives:

2-propanol

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ethyl amine

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acetaldehyde

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ethanol

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Solution

The correct option is B ethyl amine

Aldoxime and ketoxime on reduction with $L i A l H_{4}$ or $N a - C_{2} H_{5} O H$ give $1^{0}$ amine.

Option B is correct.

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Similar questions

N a / H g

C H_{3} B r + K C N (a l c) ⟶ X R e d u c t i o n ⟶ N a / C_{2} H_{5} O H Y

Y

N a B H_{4}

C_{2} H_{5} O H

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