Acetamide when treated with $B r_{2}$ and caustic soda, the product obtained is:

acetic acid

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bromacetic acid

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ethylamine

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methylamine

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Solution

The correct option is C ethylamine
The given reaction is Hoffman-bromamide degradation.
The product formed is an amine. In this case, the product formed is $C H_{3} N H_{2}$ .
$C H_{3} - O | | C - N H_{2} B r_{2} / N a O H - ------ \to C H_{3} - N H_{2}$

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