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Question

Acetic acid CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H - bonds with a total strength of 77.43 kJ per mol of dimer.
If at 27C, the equilibrium constant for the dimerization is 1.096×103, then calculate the magnitude of ΔS (in kJ) for the reaction:
2CH3COOH(g)(CH3COOH)2(g) (Round upto 2 digits after decimal and ln(1.096×103)7 and R=8.3 JK1mol1)

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Solution

ΔG= RTlnK=8.3×300×ln(1.096×103)=17430 J=17.43 kJΔG=ΔHTΔS17.43=77.43300×ΔSΔS=77.43+17.43300=0.2 kJ

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