Acetic acid is treated with $C a {(O H)}_{2}$ and the product so obtained is subjected to distillation. The final product is :

ethanal

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propanal

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propanone

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ethanol

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Solution

The correct option is B propanone
Acetic acid (as an example of a typical carboxylic acid) reacts with calcium hydroxide to form calcium acetate. This is a simple acid-base reaction which forms a salt and water:

$2 C H_{3} C O O H + {C a (O H)}_{2} ⟶ (C H 3 C O O)_{2} C a + 2 H_{2} O$
Upon heating, calcium acetate undergoes decomposition to acetone and calcium carbonate. The acetone can be distilled off from the mixture, leaving behind solid calcium carbonate:

${(C H_{3} C O O)}_{2} C a \to Δ C a C O_{3} + 2 {(C H_{3})}_{2} C = O$

At even higher temperatures calcium carbonate itself can be decomposed to calcium oxide and carbon dioxide:

$C a C O 3 Δ - \to C a O + C O$

Hence, the correct option is $C$

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Acetic acid is treated with $C a (O H)_{2})$ and the product so obtained is subjected to dry distillation. The final product is

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0^{o} C

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