Acetone is treated with excess of ethanol in the presence of HCl- The product obtained is-A- CH 3- CH 2- CH 2- C - CH 3B- OCH 3- CH 2- CH 2- C - CH 2- CH 2- CH 3C-D-

The correct option is D Aldehydes amp; Ketones react with alcohols in presence of HCl to form acetals and ketals . ...

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Reductions Involving Aldehydes or Ketones

Acetone is tr...

Question

Acetone is treated with excess of ethanol in the presence of $H C l$ . The product obtained is:

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130^{\circ} C

What is the chief product obtained when n-butane is treated with bromine in the presence of light at $130^{\circ} C$

{CH}_{3} - {CH}_{2} - Br + {CH}_{3} - {CH}_{2} - Br Na / dry ether - ------- \to The product / s formed are

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

An alkane with molecular formula $C_{6} H_{14}$ gives two monochloro alkanes on chlorination. What is the structure of alkane?

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